Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where 
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:
Substitute the respective values in the above formula.
Hence, the required probability is 0.55404.
(m - n)(r - s) Hope this helps and heve a nice day!
Answer:
D
Step-by-step explanation:
We start at the origin (we the axis cross)
We go three units to the right, then 5 units down.
We end up at the point D
1. D. (0,3)
2. B. 650
3. C. 780
Bener semua kok
semoga membantu.
kasi brainliest oi wkwkwk
<span>x1+x2+x3=0 if x1,x2,x3 > -5?
and the solutions are integer
x1= - 4 and x2+x3=4 we count (-4;4;0), (-4;0;4), (-4;3;1), (-4;1;3), (-4; 2;2), (-4;2;2)
x1= -3 and x2+x3=3 we count (-3; 0;3), (-3;3;0), (-3;1;2), (-3;2;1)
x1= -2 and x2+x3=2 we count (-2;0;2). (-2;2;0), (-2;1;1)
x1= -1 and x2+x3=1 we count (-1;0;1), (-1;1;0)
x1=0 and (0;0;0), (0;1;-1), (0;-1;1)
There are 42 solutions
Have fun</span>
