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algol13
3 years ago
15

Multiply (8x^4)(7x^2). What is the product?

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0

Answer:

200,704x

Step-by-step explanation:

(4,096x)(49x)

=200,704x

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How do I find QS here?
docker41 [41]
Answer: 12.

To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.

In the first line:
QR = 15 - 4x.

In the third line:
QR = 13x - 1 - x = 12x - 1.

Now, we have to set these equations equal to each other. 
15 - 4x = 12x - 1
15 = 16x - 1
16x = 16
x = 1

Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.
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3 years ago
Se construye cubo de madera de qué tiene 26 m de aristas y se debe cubrir todo el cubo con plástico cuántos metros cuadrados de
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Step-by-step explanation:

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3 years ago
HELP ME PLEASE!!!
Doss [256]
The 5 values needed are:
Min, Q1, Q2, Q3, Max
Order the data:
2, 3, 4, 9, 11, 12, 17, 18
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4 years ago
A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat
Marizza181 [45]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that a prior estimation for p would be \hat p =0.5 since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

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Answer:

74

Step-by-step explanation:

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