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3 years ago

Find the value of x. 3 x = [?]

Mathematics

1 answer:

satela [25.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

According to Euclidian theorem h^2 = 3*x (h : height)

36 = 3x divide both sides by 3

12 = x

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What is x in the equation -3(7-2x)+3=8x-10

damaskus [11]

Answer:

x=-4

Step-by-step explanation:

−3(7−2x)+3=8x−10

Step 1: Simplify both sides of the equation.

−3(7−2x)+3=8x−10

(−3)(7)+(−3)(−2x)+3=8x+−10(Distribute)

−21+6x+3=8x+−10

(6x)+(−21+3)=8x−10(Combine Like Terms)

6x+−18=8x−10

6x−18=8x−10

Step 2: Subtract 8x from both sides.

6x−18−8x=8x−10−8x

−2x−18=−10

Step 3: Add 18 to both sides.

−2x−18+18=−10+18

−2x=8

Step 4: Divide both sides by -2.

−2x

−2

x=−4

4 0

3 years ago

Read 2 more answers

HELP ME PLZ

Yuki888 [10]

B this is because 15y is 10 a

6 0

3 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.