The sum of the complex number 12 – 5i and –3 + 4i is 9 - i
<h3>How to sum complex number?</h3>
The sum of 12 – 5i and –3 + 4i can be done as follows:
Therefore,
12 - 5I + (-3 + 4i)
12 - 5i - 3 + 4i
Hence,
combine like terms
12 - 3 - 5i + 4i
Finally,
9 - i
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Answer:
5
Step-by-step explanation:
b^5 + 2b^3 + 7
Here,
degrees are 5 and 3.
The degree of the polynomial is the <u>highest / greatest number</u> in the degree.
Out of 3 and 5
5 is the highest / greatest number.
Hence,
the degree of the given polynomial is 5.
Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let 
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean : 
Sample standard deviation : 
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer:
(3) y = 4x
Step-by-step explanation:
In order for the equation not to change, the point (0, 0) must be on the original line and so on the line after dilation. The only equation with (0, 0) as a point on the line is y=4x.
Dilation about the origin moves all points away from the origin some multiple of their distance from the origin. If a point is on the origin, it doesn't move. We call that point the "invariant" point of the transformation. For the equation of the line not to change, the invariant point must be on the line to start with.
