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Leokris [45]
3 years ago
5

Deck of 52 cards contains 5suits: hearts, clubs, diamonds, and spades. each suit consists of cards numbered 2 through 10, a jack

, a queen, a king, and an ace.
what is a p(A or B) the probability that the card zhi qing chooses is either a three or a seven
Mathematics
1 answer:
Sidana [21]3 years ago
5 0
8/52 or roughly 15%

(ksrnakbdbwh)
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Together, teammates Pedro and Ricky 2681 base hits last season. Pedro had 285 more hits than Ricky. How many hits did each playe
lara31 [8.8K]
Pedro did 1,626 hits and ricky did 1,056. Can you please help me with my question?

6 0
3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
What is the greatest integer a, such that a^2 + 3b is less than (2b)^2, assuming that b is 5? Please answer and have a nice day!
solniwko [45]
<h3>Answer: Largest value is a = 9</h3>

===================================================

Work Shown:

b = 5

(2b)^2 = (2*5)^2 = 100

So we want the expression a^2+3b to be less than (2b)^2 = 100

We need to solve a^2 + 3b < 100 which turns into

a^2 + 3b < 100

a^2 + 3(5) < 100

a^2 + 15 < 100

after substituting in b = 5.

------------------

Let's isolate 'a'

a^2 + 15 < 100

a^2 < 100-15

a^2 < 85

a < sqrt(85)

a < 9.2195

'a' is an integer, so we round down to the nearest whole number to get a \le 9

So the greatest integer possible for 'a' is a = 9.

------------------

Check:

plug in a = 9 and b = 5

a^2 + 3b < 100

9^2 + 3(5) < 100

81 + 15 < 100

96 < 100 .... true statement

now try a = 10 and b = 5

a^2 + 3b < 100

10^2 + 3(5) < 100

100 + 15 < 100 ... you can probably already see the issue

115 < 100 ... this is false, so a = 10 doesn't work

5 0
3 years ago
PROBLEM SOLVING A game of bowling has ten frames. After five frames, your friend’s bowling score is 65 and your bowling score $x
Elodia [21]

Considering the situation described, we have that:

a. x = 65 - 8 = 57.

b. You won the game, as you scored 137 and your friend 130.

<h3>What is the equation for the situation after five frames?</h3>

Your friend's score is of 65, and your score of x is 8 less than your friend, hence the equation is:

x = 65 - 8 = 57.

<h3>What are the final scores?</h3>

Your friend score doubled, hence his/her final score is:

2 x 65 = 130.

Your score increased by 80, hence your final score is:

57 + 80 = 137.

You won the game, as you scored 137 and your friend 130.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

8 0
1 year ago
John borrowed $1200 from his credit union at 18% simple interest. He agrees to repay the loan by making
kakasveta [241]
1200 (1+.8 * 30/12) = 1740.00
1740.00 - 1200  = $540

4 0
3 years ago
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