44 lbs of onions cost $264. How many lbs of onions can you get with $156 ?

Measure each angle using a protractor

Artyom0805 [142]

Answer:

90*

Step-by-step explanation:

6 0

2 years ago

Please help with this

Anna [14]

The answer is 6f+(-6.1)

3 0

2 years ago

Read 2 more answers

A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob

Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58. </span>

4 0

3 years ago

According to the graph, what is the experimental probability of selecting the letter E?

Daniel [21]

The experimental probability of letter E is: 3/25

Step-by-step explanation:

The given diagram is the number of outcomes for each letter is given

We have to find the total number of outcomes for finding the experimental probability of letter E

So,

Total outcomes = n(S) = 5+12+8+10+6+9 = 50

Number of outcomes for Letter E = n(E) = 6

So the experimental probability will be:

$P(E) = \frac{n(E)}{n(S)}\\\\=\frac{6}{50}\\\\= \frac{3}{25}$

Hence,

The experimental probability of letter E is: 3/25

Keywords: Probability, experimental probability

Learn more about probability at:

#LearnwithBrainly

7 0

2 years ago

Find the characteristic polynomial of A. Use x for the variable in your polynomial.You do not need to factor your polynomial. A

Vesna [10]

Answer: The required characteristic polynomial of the given matrix A is $x^3+6x+11x+6=0.$

Step-by-step explanation: We are given to find the characteristic polynomial of the following 3 × 3 matrix A with unknown variable x :

$A=\left[\begin{array}{ccc}0&0&1\\4&-3&4\\-2&0&-3\end{array}\right].$

We know that

for any square matrix M, the characteristic polynomial is given by

$|M-xI|=0,$ where I is an identity matrix of same order as M.

Therefore, the characteristic polynomial of matrix A is

$|A-xI|=0\\\\\\\Rightarrow \left|\left[\begin{array}{ccc}0&0&1\\4&-3&4\\-2&0&-3\end{array}\right]-x\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\right|=0\\\\\\\Rightarrow \left|\left[\begin{array}{ccc}-x&0&1\\4&-3-x&4\\-2&0&-3-x\end{array}\right] \right|=0\\\\\\\Rightarrow -x(3+x)^2+1(0-6-2x)=0\\\\\Rightarrow (x+3)(-3x-x^2-2)=0\\\\\Rightarrow (x+3)(x^2+3x+2)=0\\\\\Rightarrow x^3+6x+11x+6=0.$

Thus, the required characteristic polynomial of the given matrix A is $x^3+6x+11x+6=0.$

6 0

2 years ago