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blsea [12.9K]
3 years ago
10

-2/3- (-3/4) Simplify if needed Brainliest Also, 5/6+5/12

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

Step-by-step explanation:

Given

-\frac{2}{3} - (-\frac{3}{4})

Required

Solve:

-\frac{2}{3} - (-\frac{3}{4})

Open bracket

-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}

Take LCM

-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12}

Take LCM

\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}

\frac{5}{6} + \frac{5}{12} = \frac{15}{12}

Divide by 3/3

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

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Answer:

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Step-by-step explanation:

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Tamika makes a 5.5% commission selling electronics. How much commission does she make if she sells a flat-screen TV for $10,000?
strojnjashka [21]

Answer: She makes $550

Step-by-step explanation:

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7 0
3 years ago
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How many pounds of cashews that cost $14 per pound must be mixed with 5 pounds of peanuts that cost $6.50 per pound to make mixe
Fantom [35]

The amount of cashew mixed is 5 pounds

<h3>Word problem on total cost</h3>

Cost of 1 pound of cashew = $14

Cost of 1 pound of peanut = $6.50

Total cost of 1 pound of the mixed nuts = $10.25

Cost of 5 pounds of peanuts = 5 x $6.50

Cost of 5 pounds of peanuts = $32.50

Let the amount of cashew  be x

Total cost of x cashew = 14x

Total amount of the mixed nuts = x + 5

Total cost of the mixed nuts = 10.25(x+5)

Total cost of the mixed nuts = 10.25x + 51.25

14x  +  32.50  =  10.25x  +  51.25

14x - 10.25x  =  51.25  -  32.50

3.75x  =  18.75

x  =  18.75/3.75

x  =  5

Therefore, the amount of cashew mixed is 5 pounds

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8 0
2 years ago
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<h3>Answer:</h3>

Mean: 17.2

Median: 18

Mode: 18

<h3>Solution:</h3>

Mean: The sum of all observation divided by several observation

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  • 86÷5=
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Median:it is the middlemost observation of data arraged in increasing or decreasing order of values

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Mode:it is the value that occurs frequently in a set of data

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2 years ago
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