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3 years ago

9

Joseph has 3,134 pieces of paper in his classroom.emily has 5,229 pieces of paper in her classroom.how many pieces of paper do t

hey have in both classrooms

2 answers:

AysviL [449]3 years ago

7 0

2095 is the correct answer

Mila [183]3 years ago

7 0

8,363 is the answer

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Find the length of a line segment CD with endpoint C at (-3,1) and endpoint D at (5,6)

lutik1710 [3]

I believe your length would be 8, because -3 to get to 0 is 3 then after that you still have 5 so you add them and get 8

8 0

2 years ago

What polynomails has the roots of -6, -4 ,and 1? A)x³-9x²-22x+24 B) x³-x²-26x-24 C) x³+x²-26x+24 D)x³+9x²+14x-24.

never [62]

Answer:

x = 1 or x = -4 or x = -6 thus d: is your answer

Step-by-step explanation:

Solve for x over the real numbers:

x^3 + 9 x^2 + 14 x - 24 = 0

The left hand side factors into a product with three terms:

(x - 1) (x + 4) (x + 6) = 0

Split into three equations:

x - 1 = 0 or x + 4 = 0 or x + 6 = 0

Add 1 to both sides:

x = 1 or x + 4 = 0 or x + 6 = 0

Subtract 4 from both sides:

x = 1 or x = -4 or x + 6 = 0

Subtract 6 from both sides:

Answer: x = 1 or x = -4 or x = -6

4 0

2 years ago

Read 2 more answers

Which of the following statements is the only<br> sentence that is error-free?

Ray Of Light [21]

I don’t really know what the answer is

5 0

2 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st

DanielleElmas [232]

Question: The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B) = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0

2 years ago