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Vanyuwa [196]
3 years ago
9

What is the rule used to reflect the triangle ABC to its image?

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0

Answer:

The rule used to reflect Δ ABC to its image is Reflect over y = x ⇒ B

Step-by-step explanation:

  • If the point (x, y) reflected across the x-axis , then its image is (x, -y)
  • If the point (x, y) reflected across the y-axis , then its image is (-x, y)
  • If the point (x, y) reflected across the line y = x , then its image is (y, x)
  • If the point (x, y) reflected across the line y = -x , then its image is (-y, -x)

From the given figure

∵ The coordinates of point A are (-4.5, 6)

∵ The coordinates of point A' are (6, -4.5)

→ The coordinates are switched ⇒ 3rd rule

∴ Point A is reflected over the line y = x

∴ Δ ABC is reflected over the line y = x

∴ The rule used to reflect Δ ABC to its image is Reflect over y = x

<em>Note: Point B' on the graph should be C' and point C' should be B' (correct it)</em>

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Answer:

g(4)=f(2)

Step-by-step explanation:

f(2)=3(2)-1

f(2)=6-1

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We then get:

g(x)=f(2)

subsitute 5 for f(2)

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Which expressions are equivalent to ln x 2 ln 5 ln 1? Check all that apply. 2 ln 5x ln (x 26) ln 25x ln 1 ln 25x.
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Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,

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Given information-

The expression given in the problem is,

\ln x+2 \ln 5 +\ln1

<h3>Equivalent expression-</h3>

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.

For given expression,

\ln x+2 \ln 5 +\ln1

As the above function is the function of <em>x. </em>Thus it can be written as,

f(x)=\ln x+2 \ln 5 +\ln1

<h3>Logarithm power rule</h3>

Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

f(x)=\ln x+ \ln 5^2 +\ln1\\&#10;f(x)=\ln x+ \ln 25 +\ln1

Now the value of \ln 1 is equal to the zero. Thus,

f(x)=0+\ln 25 +\ln1\\&#10;f(x)=0+\ln 25 +\ln1\\&#10;f(x)=\ln 25 +\ln1\\&#10;f(x)=\ln 25 +0\\&#10;f(x)=\ln 25

Hence the expressions which are equivalent to the given expression are,

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Learn more about the equivalent expression here;

brainly.com/question/10628562

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