Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
About 5 hours. I did this by dividing and rounding 276 by 62. Hope this helps!
Answer:
Approximately mMK is 53 degrees
Step-by-step explanation:
Here, we want to find the length of MK
As we can see, we have a right triangle at LNK
so
let us find the angle at L first
9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L
so the trigonometric identity that connects adjacent to the hypotenuse is the cosine
It is the ratio of the adjacent to the hypotenuse
So;
cos L = 9/15
L = arc cos (9/15)
L = 53.13 degree
Approximately, L = 53 degrees
so now, we want to get the arc length MK
We are to use the angle-arc relationship here
Using this; arc length MK is equal to the measure of L at the center which is 53 degrees
B I really believe you just got to read it carefully
Answer:
Step-by-step explanation:
1. bottom left
