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3 years ago

Jason's mom drove at 100 km/h for a 160 km trip. How much longer would

Mathematics

2 answers:

Delvig [45]3 years ago

8 0

Answer:

10 minutes

Step-by-step explanation:

the trip wouldve taken 10 minutes longer because the car was going 10km slower

choli [55]3 years ago

4 0

Answer:

Here is the way to get the answer

Step-by-step explanation:We use the formule: t=S/v. So:

+ t1= 160/100 = 8/5 hrs = 5760''

+ t2= 160/90 = 16/9 hrs = 6400''

=> t2-t1= 6400 - 5760 = 640'' = 10'40''

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3x + 7y = 21 –3x – 7y = 42<br> Solve the system of equations?

likoan [24]

9514 1404 393

Answer:

no solution

Step-by-step explanation:

The equations describe parallel lines. There are no values of x and y that will satisfy both equations.

In standard form, the two equations are ...

3x +7y = 21

3x +7y = -42 . . . . . with positive leading coefficient

If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.

8 0

3 years ago

Drag steps in the given order to evaluate this expression. (−5)(2)−2(−3)+3 ( -5 )( 2 ) - 2 ( -3 ) + 3

Snowcat [4.5K]

(−5)(2)−2(−3)+3 ( -5 )( 2 ) - 2 ( -3 ) + 3

=-10+6-30+6+3

=15-40

=-25

6 0

3 years ago

How do you write y=25x-56 in standard form?

Tcecarenko [31]

To put a slope-intercept into standard form, you have to first cancel out the fractions. So:
$y = \frac{2}{5}x - \frac{5}{6}$

Turns into:
$(5)(6)y = (\frac{2}{5}x - \frac{5}{6})(5)(6)$

Simplify:
$30y = (\frac{2}{5}x - \frac{5}{6})(30)$

Distribute:
$30y = 12x- 25$

Since you want to get x and y on the same side, you subtract 12x from both sides to get:
$-12x+30y = -25$

So, your answer is C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.

6 0

4 years ago

WILL GIVE BRAINLIEST PLEAAE HELP

iren2701 [21]

Answer:

you would get 15% of the 2,000$

Step-by-step explanation:

hope it helps pls give brainly

6 0

3 years ago

Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1

o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

$y=f(\frac{1}{5}x)$

1/5 is multiplied with x in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> $(\frac{1}{\frac{1}{5}} , 19)= (5,19)$

So (5,19) lies on the graph of the transformed function y = f(1/5x)

8 0

3 years ago