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Stells [14]
3 years ago
5

College algebra pls help

Mathematics
1 answer:
lana [24]3 years ago
4 0
Plug in 7 for x and 24 for v
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Stephanie is hosting an art show and she would like to raise at least $800. She plans on
Masteriza [31]

Answer: 10, 15

Step-by-step explanation:

Given

Stephanie wants to raise at least $800

she plans on selling VIP tickets for $20 each and general admission for $40 each

suppose there are x and y tickets for VIP and general admission

\therefore x+y\leq 25\\\\\Rightarrow 20x+40y\geq 800

solving above two inequality

Stephanie must sell 10 tickets for VIP and 15 tickets for general admission

7 0
3 years ago
In the diagram below, ΔABC is inscribed in circle P. The distances from the center of circle P to each side of the triangle are
4vir4ik [10]
Supposing the sides with 6 and 8 is a right angle, you can create a new line from C and P, and find the length using the equation of a²+b²=c² or 6²+8²=c², with c equaling the radius of the circle.

After finding c, you will have to find the length from C to the midpoint of AC, using the same equation a²+b²=c². If both the lengths of C to the midpoint of AC, and A to the midpoint of AC are equal, you can do b+b to find the length of AC.

Using the same approach, you can find AB. Hope this makes sense, if not, I can clarify more.
5 0
3 years ago
Don’t mind the writing. Just trying to see if this is right?
LuckyWell [14K]

Answer:


Step-by-step explanation:

Yep you are 100% correct grate job!!

4 0
2 years ago
Read 2 more answers
Please help. Look at screenshot
Citrus2011 [14]

Answer:

a.

<u>Increasing:</u>

x < 0

x > 2

<u>Decreasing:</u>

0 < x < 2

b.

-1 < x < 2

x > 2

c.

x < -1

Step-by-step explanation:

a.

Function is increasing when it is going up as we go rightward

Function is decreasing when it is going down as we go rightward

We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).

So,

<u>Increasing:</u>

x < 0

x > 2

The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:

<u>Decreasing:</u>

0 < x < 2

b.

When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].

Looking at the graph, it is

from -1 to 2 (x axis)

and 2 to positive infinity

We can write:

-1 < x < 2

x > 2

c.

Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.

This will be the other intervals than the ones we mentioned above in part (b).

Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:

x < -1

4 0
3 years ago
Add the product of 5 and 6 with the product of 3 and 7
xz_007 [3.2K]

It is 51.                                           

5x6=30

3x7=21

30+21=51

Hope that I was of help.

5 0
2 years ago
Read 2 more answers
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