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3 years ago

What is the force acting on a 16 kg object accelerating at 2.0 m/s2

Mathematics

1 answer:

alexira [117]3 years ago

6 0

Answer:

32 n

Step-by-step explanation:

I had the same problem but I used a net force calculator the formula is F=MA so it would be 32=16/2.0 :)

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Tell whether the triangle is a right triangle. Please help

schepotkina [342]

Pythagorean Theorem:
a^2 + b^2 = c^2
10. 144 + 196 = 340
Yes, it is a right triangle

11. 256 + 361 does not equal 684 so it is not a right triangle

4 0

3 years ago

What would be the equation to you have a part time job. You work for 3h on Friday and 6h on Saturday. You also recieve an allowa

HACTEHA [7]

Answer:

Step-by-step explanation:

So, to go about your question, we must first ask, how many hours a week is being worked?

In this problem, that is 9 hours per week.

Next, we must question how much per week is made

That is $92 per week

Finally, we must determine if the allowance is occuring many times in the week or just once.

In this problem, that is only occuring once for the week.

So, the equation we must setup is 9x +20 =92.

To solve the equation, we need to subtract 20 on both sides to isolate the variable, x.

9x+20=92

-20 -20

Now our equation is

9x=72

Now, to finally get x by itself or to isolate x, you should divide 9 on both sides to cancel out the 9 being multiplied by the x.

9x=72

9 9

x=8 because of 72/9 is equal to 8.

I hope this helps, and I will answer any questions you have.

5 0

3 years ago

On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

4 years ago

22 1 point If f (x) = 7– 41, what is f (-10)?

Anettt [7]

Answer:

f(x)+41 f(-10)=7

Step-by-step explanation:

5 0

3 years ago

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Alik [6]

Answer: We can't even see the whole picture my dude

Step-by-step explanation:

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3 years ago

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