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vovangra [49]
3 years ago
13

Is Cu2+(aq) + 2e− ---------------> Cu(s) oxidation or reduction?​

Business
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

Reduction: Cu2+ + 2e- → Cu Oxidation: 2H2O → O2- + H+ + 4e- Overall: 2Cu2+ + 2H2O → 2Cu + O2- + H+ Cu2+ is reduced because it gains 2 electrons in order to become Cu and reduction is the gain of electrons. plz make me branilist

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