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Naily [24]
3 years ago
15

Help me please I need help 2

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer:

26.6 meters

Step-by-step explanation:

Tan(x) = \frac{opp}{adj}

Tan(28)  = \frac{x}{50}

x = 26.6m

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The other part of your ratio is missing
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Sarah is a computer engineer and manager and works for a software company. She receives a
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Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 \times 1938 = $969000

8 0
3 years ago
The South Company cash account had a balance of $1,202.50 on January 31. A deposit, made on the 31st, in the amount of $100.05 w
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Answer:

$1326

Step-by-step explanation:

Follow the format of the reconciliation statement

The adjusted cash balances should match

Cash balance as per the bank statement, January 31        1421.95

Add: Deposit in transit                                                           100.05

Deduct: Outstanding checks                                                  <u>(196)</u>

Adjusted cash balance                                                            <u>1326</u>

Balance as per depositor's record, January 31                    1202.5

Subtract: NSF check                                                                  (18)

Subtract: Service charges                                                         (8.5)

Add: receivable collected                                                          <u>150</u>

Adjusted cash balance                                                              <u>1326</u>

The reconciled amount is $1326.

!!

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LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

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Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

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3 years ago
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