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katovenus [111]
3 years ago
7

Find tan 0, where is the angle shown give an exact value not a decimal approximation plz help due soon !

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

tanθ = \frac{15}{8}

Step-by-step explanation:

let the unknown side be x , then

Using Pythagoras' identity in the right triangle

x² + 5² = 17²

x² + 25 = 289 ( subtract 25 from both sides )

x² = 225 ( take the square root of both sides )

x = \sqrt{225} = 15

Then

tanθ = \frac{opposite}{adjacent} = \frac{15}{8}

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3 years ago
Solve the equation.<br> у+ 3 = -у +9<br> Оy = 1<br> Оy= 3<br> O y=6<br> Оy= 9
Triss [41]

Answer:

y = 3

Step-by-step explanation:

Solve for y:

y + 3 = 9 - y

Add y to both sides:

y + y + 3 = (y - y) + 9

y - y = 0:

y + y + 3 = 9

y + y = 2 y:

2 y + 3 = 9

Subtract 3 from both sides:

2 y + (3 - 3) = 9 - 3

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2 y = 9 - 3

9 - 3 = 6:

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Divide both sides of 2 y = 6 by 2:

(2 y)/2 = 6/2

2/2 = 1:

y = 6/2

The gcd of 6 and 2 is 2, so 6/2 = (2×3)/(2×1) = 2/2×3 = 3:

Answer:  y = 3

5 0
4 years ago
Read 2 more answers
If y=(x^2-4)^5(3x+4)^4
alexira [117]

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Step-by-step explanation:

y=(x^2-4)^5(3x+4)^4

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y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

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2 years ago
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The red goes into the bottom plane and the blue stays on the top
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The speed of the current is 7 mph. The boat travels three times slower against the current than with the current. What is the sp
kotykmax [81]
Let the speed of the boat be x
so going against the current the speed is x-7
going with the current the speed is x+7

let the distance be d
time = distance / speed
time to go against the current = d/(x-7)
time to go with the current = d/(x+7)

time going against the current is 3 times going <span>with the current
</span>
d/(x-7) = 3d/(x+7)     ⇒⇒⇒ divide by d 
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2x = 28
x = 14

So, the speed of the boat in still water is = 14 mph
3 0
4 years ago
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