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2 years ago

Which of the following represents how the problem 3/4 ÷ 7/8 would be changed before it could be solved

Mathematics

2 answers:

BartSMP [9]2 years ago

4 0

Answer:

Step-by-step explanation:

1+12

⅘444444444444444444444444

Anika [276]2 years ago

3 0

Answer:

is there a picture. wirh it

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I have asked so many times and no one will answer. :(

andrew-mc [135]

Answer:

1) $\frac{1}{2^7}$ ; 2) $11^7$

Step-by-step explanation:

1) Using the Power of a Fraction Rule $(\frac{a}{b} )^x = (\frac{a^x}{b^x} )$ ,

$(\frac{1}{2} )^7 = (\frac{1^7}{2^7} )$ , which can just be simplified to $\frac{1}{2^7}$ .

2) Using the Negative Exponent Rule, $a^{-x} = \frac{1}{a^{x}}$ ,

$(\frac{1}{11} )^{-7} = \frac{1}{\frac{1}{11^7}}$ , which can be simplified to $11^7$ .

4 0

2 years ago

Solve the inequality, then identify the graph of the

Leviafan [203]

Hope this is straightforward.

7 0

2 years ago

It takes a turtle 3 ¼ hours to walk 1 ½ miles. How many hours does it take to walk one mile?

Norma-Jean [14]

Answer:

It will take 6/13 hours to walk one mile

Step-by-step explanation:

Here, we want to calculate the number of hours it take to walk one mile

From the question, 1 1/2 miles take 3 1/4 hours

the number of hours it will take to walk 1 mile will be;

1 1/2 divided by 3 1/4

= 3/2 divided by 13/4

= 3/2 * 4/13 = 6/13 hours

4 0

2 years ago

Find the value of x. 2x 120° 700 A. 55 B. 35 C. 25 D. 10

monitta

Answer:

for this question you need to take the 12p and 700 and add then dived by 2x which then gives you your answer

7 0

2 years ago

Read 2 more answers

80% of an airline's flights depart on-time and 20% do not. Of those that depart on-time, 95% arrive on-time. Of those that depar

Dmitry_Shevchenko [17]

Answer:

0.78

Step-by-step explanation:

given that 80% of an airline's flights depart on-time and 20% do not.

Of those that depart on-time, 95% arrive on-time. Of those that depart late, 10% arrive on-time

Let A be the event that flight departs on time.

Now A and A' are mutually exclusive and exhaustive

Let B be the event the flight arrives on time

Using total probability calculation we have

the chance of someone taking a flight that will arrive on-time

= P(B)

= $P(A)+P(A'B)\\= 0.80(0.95) +0.20(0.10)\\= 0.76+0.02\\=0.78$

4 0

2 years ago