A stack of cards is numbered 1 through 50 if a student selects a card what is the probability that the student will select a car
d that has both the same number in the ones place in the tens place write the answer in decimal form
1 answer:
Answer:
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
Step-by-step explanation:
To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.
f = favorable events
we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place
11 ; 22 ; 33 ; 44
as we can see there are 4 numbers
f = 4
p = possible events
the number of possible events is given by the number of cards in the deck
p = 50
4/50 = 0.08
The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08
You might be interested in
Answer:
Step-by-step explanation:
3b⁵ + 15b⁴ - 18b⁷ = 3b⁵ + [3*5*b⁴] - [6*3*b⁷]
=3b⁴*( b + 5 - 6b³)
Answer:
-8 + 3.2z
Step-by-step explanation:
- when there is a "+" in front of an expression in parentheses, the expression remains the same
- -2 + 6.45z - 6 - 3.25z
- calculate the difference
-8 + 6.45z - 3.25z
collect like terms
-8 + 3.2z
Answer: D or y= 4/3+ 18
Step-by-step explanation:
You want to use the distributive property for this one:
-7k + 21
Your answer should be the very bottom left one.
Hopefully thta helped! :)
