Ask question

Ask question

All categories

4 years ago

15

Can someone help me please?

1 answer:

antiseptic1488 [7]4 years ago

4 0

21 >
22 <
23 <
24 <
25 >
26 <
27 >
28 <
29 >
30 <
31 <
32 <
33 √16,4.2,39/8
34√24,5.1,√33
I hope this helps you :)

You might be interested in

If AP 10 - 12. what is the perimeter of quadrilateral TAEO (a) 56 (b)64 (c)72 (d)76

BlackZzzverrR [31]

Husofjwiebd9ks ueijddlonf durnkofbjus yuebejuiiiiiiiiijjd dijdjdjdnsjduwjwuwhw

4 0

3 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

3 years ago

A boat travels 432km in 24 hours how far can it travel in 16 hours?

pickupchik [31]

The answer is 288 km!

3 0

4 years ago

Find the zeros or roots for the quadratic expression 2^2−8−10. Must show all work to receive credit

Sav [38]

Answer:

x = -1,5

Step-by-step explanation:

2x² - 8x - 10

2x² - 10x + 2x - 10

2x(x - 5) + 2(x - 5)

(x - 5)(2x + 2)

x = 5 x = -2/2

x = -1,5

5 0

3 years ago

4d+q=14.95. Find d and q.

goldenfox [79]

Answer:

I love algebra anyways

The ans is in the picture with the steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

6 0

3 years ago