Question

Find the value of the variable.

Answer 1

Answer:

x=8

base side of isosceles triangle

y=√{8²+8²}=8√2

Answer 2

Answer:

x = 8, y = $8\sqrt{2}$

Step-by-step explanation:

$a^2+b^2=c^2$

$8^2+8^2=c^2$      Both 8 and x sides are congruent so they're equal.

$64+64=c^2$      Add 64 + 64.

$c^2=128$           Square root 128

$c^2=8\sqrt{2}$

Final answers: x = 8, y = $8\sqrt{2}$