3 years ago

Identify a pair of parallel lines in the given figure.

Mathematics

1 answer:

Alenkasestr [34]3 years ago

7 0

Parallel Lines: lines in a plane which do not meet. they do not intersect at any point, so your answer is B.

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If 3x^2+3y^2=42 and xy =-15.Find the value (x-y)^2

Alexxandr [17]

Answer:

Step-by-step explanation:

Given, 3x^2 + 3y^2 = 42

=>3(x^2 + y^2) = 42 =>x^2 + y^2 = 42/3= 14

Thus,

= (x - y)^2

= x^2 + y^2 - 2xy

= (x^2 + y^2) - 2xy

= 14 - 2(-15)

= 14 + 30

= 44

4 0

3 years ago

Expand and simply <br> 4(2d + 3) – 2(3d – 5)

Brut [27]

Answer:

8d+12-6d+10

2d+22

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!

svetlana [45]

We know in these kind of triangles that have a 90 degrees angle, we can do:

${a}^{2} + {b}^{2} = {c}^{2}$

so the first question:

$\sqrt{ {99}^{2} + {20}^{2} } = 101$

and then:

$b = \sqrt{ {17}^{2} - {15}^{2} } = 8$

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

$\frac{ \sqrt{15} }{ \sqrt{15} } = 1$

so , now multiply:

$\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}$

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,