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bogdanovich [222]
2 years ago
11

Factor the expression using the GCF.

Mathematics
2 answers:
ss7ja [257]2 years ago
7 0

Answer:

= 3 (3x + 5y)

Step-by-step explanation:

First find the GCF of 9 and 15 which would be 3. Then the GCF which is 3 is placed on the left of the parentheses. then you plug in the numbers. So 9x divided by 3 is 3x, and 15y divided by 3 is 5y.

stellarik [79]2 years ago
5 0

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\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

               Factor the expression 9x+15y using the GCF.

\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

First, let's find the GCF of this expression.

Expressions, like numbers, have GCF's, and we're asked to find it.

The factors of the first term, 9x, are:-

1, x, 3

The factors of the second term, 15y, are:-

1, y, 3, 5

Common factors:-

1, 3

Greatest common factor (GCF):-

3

So we divide both terms by 3:-

3(3x+5y)

<h3>Good luck.</h3>

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A softball player made a hit 34 times in the last 170 times at bat . Find the probability that the softball player will get a hi
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1/5

Step-by-step explanation:

34/170 = 1/5

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What is the value of y when line m is parallel to line n?
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Angles B and D are supplementary angles, so if B's angle is 30 degrees, then D's angle at y would be 150, since they have to add to 180.
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Solve the following quadratics. State the FACTORS AND SOLUTIONS. 1. 2x^2 - 7x + 3 2. 3x^2 + 7x +2
tekilochka [14]

Answer:

1. x = 3, 1/2 (solutions); (x - 3)(2x - 1) (factors)

2. x = -1/3, -2 (solutions); (3x + 1)(x + 2) (factors)

Step-by-step explanation:

<u>1. 2x^2 - 7x + 3</u>

To solve problem 1, you will need to identify your a, b, and c values in this quadratic function.

Since this problem is in standard form, it will be easy to identify these values. The standard form of a quadratic function is ax^2 + bx + c.

The a value is 2, the b value is -7, and the c value is 3 if we use our standard form and see which numbers are plugged into it.

Since we know that

  • a = 2
  • b = -7
  • c = 3

we can use the quadratic formula: x = \frac{-b~\pm~\sqrt{b^2~-~4ac} }{2a}

Substitute the a, b, and c values into the quadratic formula: x=\frac{-(-7)\pm\sqrt{(-7)^2-4(2)(3)} }{2(2)}

Now simplify using the laws of pemdas: x=\frac{7\pm\sqrt{(49)-(24)} }{4}

Simplify even further: x=\frac{7\pm\sqrt{(25)} }{4} \rightarrow x=\frac{7\pm (5) }{4}

Now split this equation into two equations to solve for x: x=\frac{12 }{4} ~~and~~ x=\frac{2 }{4}

12/4 can be simplified to 3, and 2/4 can be simplified to 1/2.

This means your solutions to problem 1 is 3, 1/2.

\boxed {x=3,\frac{1}{2} }

There is also another way to solve for the quadratic functions, and this was by factoring.

If you factor 2x^2 - 7x + 3 using the bottoms-up method, you will get (x - 3)(2x - 1).

After factoring, solving for the solutions is simple because all you have to do is set each factor to 0.

  • x - 3 = 0
  • 2x - 1 = 0

After solving for x by adding 3 to both sides, or by adding 1 to both sides then dividing by 2, you will end up with the same solutions: x = 3 and x = 1/2.

<u>2. 3x^2 + 7x + 2</u>

To save time I'll be using the bottoms-up factoring method, but remember to refer back to problem 1 (quadratic formula) if you prefer that method.

Factor this quadratic function using the bottoms-up method. After factoring you will have (3x + 1)(x + 2). These are your factors.

Now to solve for x and find the solutions of the quadratic function, you will set both factors equal to 0.

  • 3x + 1 = 0
  • x + 2 = 0

Solve.

<u>First factor:</u> 3x + 1 = 0

Subtract 1 from both sides.

3x = -1

Divide both sides by 3.

x = -1/3

<u>Second factor:</u> x + 2 = 0

Subtract 2 from both sides.

x = -2

Your solutions are x = -1/3 and x = -2.

\boxed {x = -\frac{1}{3} , -2}

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Answer:

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Or

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xy = 4.32

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x = 3y

3y² = 4.32

y² = 1.44

y = +/- 1.2

x = +/- 3.6

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