By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
To learn more on quadratic equations: brainly.com/question/17177510
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4: A school has 314 boys & 310 girls. If they are to be grouped into equal classes of 26 each , how many classes will there be?
314 boys + 310 girls = 624
If they are grouped into classes of 26 students each, how many class will there be?
130 students = 5 classes
Therefore
260 students = 10 classes
260 x 2 = 520 = 20 classes
26 x 24 = 624
Number of classes = 24
Question 5).
Jim worked 48 weeks last year. Each week he worked 38 hours. If he worked an additional 240 hours of overtime, how many hours did he work in all?
Solution:
48 weeks
24hrs × 7 = 168hrs
168 x 48 = 8,064
Additional 240hrs
= 168hrs = 7 days (a week)
240hrs - 168 = 72 (3days)
168 + 72
= 240hrs + 8, 064
= 8, 304 hrs
The 31st term of this sequence is 189.
9, 15, 21, 27, 33 (5), 39, 45, 51, 57, 63 (10), 69, 75, 81, 87, 93 (15), 99, 105, 111, 117, 123 (20), 129, 135, 141, 147, 153 (25), 159, 165, 171, 177, 183 (30), 189.
Answer:
3.8 seconds
Step-by-step explanation:
Given equation
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)
Now make two fractions and solve for x
t= 
=-0.0815
t= 
=3.83
So answer is 3.8 seconds
