Consider rolling a fair die twice and tossing a fair coin eleven times. Assume that all the tosses and rolls are independent. Th

Question

2 years ago

14

e chance that the total number of heads in all the coin tosses equals 10 is (Q3)

1 answer:

marin [14] · Answer 1 · 2022-07-15T14:28:06+03:00

Answer:

0.005371

Step-by-step explanation:

Given that a fair coin is tossed 11 times.

Since coin is fair probability for head p = 0.5 and q = prob for tail =0.5

Each trial is independent of the other. Hence X no of heads is binomial with $n = 11 and p =0.5$

Prob for getting 10 heads out of 11 tosses

=P(X=10)

= $11C10 (0.5)^{10} (0.5)\\= 0.005371$