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3 years ago

Please help!! Will mark brainliest

Mathematics

1 answer:

lara31 [8.8K]3 years ago

8 0

Answer:

y = -4x -2

Step-by-step explanation:

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Mike has 1/8 of a teaspoon How many times should Mike use this teaspoon to measure 4 teaspoons of vanilla extract?

nadya68 [22]

Answer:

32 times

Step-by-step explanation:

1/8 x 8= 1

1/8 x 32= 4

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3 years ago

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Each side of a square is increasing at a rate of 6cm/s. At what rate is the area of the square increasing when the area of the s

diamong [38]

Area of a square = length²
A = x²
16 = x²; x = 4
dA/dx = 2x cm²/s
dx/dt = 6 cm/s
Using chain rule:
dA/dt = dA/dx * dx/dt
dA/dt = 2x * 6
dA/dt = 12x
At x = 4,
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4 years ago

What is the length of the hypotenuse of the triangle?

sergey [27]

If you use the pothaorian theorym (A squared + B squared= C squared) youll be able to figure out the right answer is 65.

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3 years ago

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3/7x+5=8 1) 7 2/3 2) 7 3) -7

Aleks04 [339]

3/7 x+5=8
3/7 x=3
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The answer is (2)

5 0

3 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago