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Blizzard [7]
2 years ago
12

Here are the numbers of times 11 people ate out last month. 4, 6, 6, 6, 3, 7, 3, 3, 7, 6,3

Mathematics
2 answers:
sdas [7]2 years ago
6 0

Answer:

ok but what am I supposed to do with it?

Step-by-step explanation:

Serhud [2]2 years ago
5 0

Answer:

uhm

Step-by-step explanation:

I think you forgot to ask the question??

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Steven earns extra money babysitting. He charges $26.25 for 3 hours and $70.00 for 8 hours.
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Luisa and Connor had $360 altogether . After Connor gave Luisa 2/5 of his money, she had the same amount of money has he did. Ho
Liula [17]

Answer:

$300

Step-by-step explanation:

Let's say that L is the amount of money Luisa had in the beginning, and C is the amount of money Connor had in the beginning.

C + L = 360

C - 2/5 C = L + 2/5 C

Simplifying the second equation:

3/5 C = L + 2/5 C

1/5 C = L

Substituting into the first equation:

C + 1/5 C = 360

6/5 C = 360

C = 300

Connor originally had $300, and Luisa $60.  Connor gave Luisa $120, and they both had $180.

8 0
3 years ago
What is the common ratio for this geometric sequence?
grin007 [14]
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3 0
3 years ago
How many hours will a car traveling at 65 miles per hour take to catch up to a car traveling at 55 miles per hour if the slower
son4ous [18]

It will take the first car 5.5 hours to catch up to the second car.

Step-by-step explanation:

Speed of second car = 55 miles per hour

As the car has started one hour before; it has already traveled

Distance = Speed * Time

Distance = 55*1 = 55 miles

Let,

x be the number of hours.

Distance covered in x hours = 55x

S(x) = 55x+55

Speed of first car = 65 miles per hour

Distance covered in x hours = 65x

F(x) = 65x

For catching up;

F(x) = S(x)

65x=55x+55\\65x-55x=55\\10x=55

Dividing both sides by 10

\frac{10x}{10}=\frac{55}{10}\\x=5.5

It will take the first car 5.5 hours to catch up to the second car.

Keywords: speed, distance

Learn more about speed at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrainly

8 0
3 years ago
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