The probability for choosing green and red is 
<u>Solution:</u>
Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.
We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?
Now, we know that,

So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4

And now, total outcomes will be only 3 as we are not replacing the picked marble.

Hence, the probability for choosing green and red is 
Answer:
D
Step-by-step explanation:
Probability that the die will show an even number
in one rolling is 3/6=0,5 = p
We have formula for repeating rolling
n!/(r!(n-r)!) p^r (1-p)^(n-r)
n = how many times we repeat rolling = 6
r = how many times we want something to happen
(show an even number exactly two times) = 2
15 *(0,5)^2 *(0,5)^4 = 0,234375
Graph it on the Ti-84 and use the trace function to find the intersection.
The answer is
(-3,3)
You would put in 12 for x since there are 12 months in a year. Then you would multiply 12 by 35, and add 70.