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mote1985 [20]
3 years ago
6

Which of the following numbers is closer to the area of a circle with a radius of 2.1

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
5 0
B. 11.33 is closer to the area of a circle with a radius of 2.1
Ipatiy [6.2K]3 years ago
4 0
The answer will be C.13.85. A=πr^2, so A=π2.1^2≈13.85. As a result, the area of the circle is about 13.85. Okay, π=3.14, and r^2=2.1×2.1=4.41. Then, 4.41×3.14≈13.85 to find the area of this circle. Hope it help!
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The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

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satela [25.4K]

Answer:

x = 2

Step-by-step explanation:

5 ( 6x - 4 ) = 20 + 4 ( 3 + x )

30x - 20 = 20 + 12 + 4x

30x - 20 = 32 + 4x

26x = 52

x = 2

8 0
3 years ago
Read 2 more answers
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