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stepan [7]
2 years ago
11

(x^8+2x^4+1)+(2x^4+x^2+1)

Mathematics
1 answer:
Arada [10]2 years ago
3 0

Your problem → (x^8+2x^4+1)+(2x^4+x^2+1)

(x^8+2x^4+1)+(2x^4+x^2+1)

=x^8 + 2x^4 + 1 + 2x^4 + x^2+1

=x^8+2x^4+2x^4+x^2+1+1

=x^8+4x^4+x^2+2

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7 0
3 years ago
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That would be

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5 0
2 years ago
What is the length of x?
Marat540 [252]

Answer:

The length of 'x' is 4

Step-by-step explanation:

We can use the pythagorean theorem to solve this.

The pythagorean theorem is:

a ^{2}  + b^{2}  =  {c}^{2}

a ^{2}  + b^{2} =  c^{2}  \\  {3}^{2}  +  {b}^{2}  = 5^{2}  \\ 9 +   {b}^{2}  = 25 \\  \frac{ - 9 \:  \:  \:  \:  \:  \:  \:  \:  =  - 9}{b ^{2}  =  \sqrt{16} }  \\ b = 4

Therefore x = 4

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