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3 years ago

Plz help me solve this

Mathematics

2 answers:

alex41 [277]3 years ago

7 0

1338.68
i think im not that good at this subject but hope you get it correct and pass, all positive energies to you!!

alexandr402 [8]3 years ago

4 0

Answer:

1338.68 meters

Step-by-step explanation:

Perimeter is all of the lengths of the sides added together.

50.9m + 50.9m + 618.44m + 618.44m = 1338.68m

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

How do you get the volume of a triangular prism?

lisov135 [29]

The equation for that is V = 1/2 A x C x H

7 0

3 years ago

Read 2 more answers

Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3

Neporo4naja [7]

Answer:

Step-by-step explanation:

hello,

because of the end behaviour the constant in $x^2$ should be positive so we have a) or d)

f(0)=-3 in both cases

for A) f(x)=

$x^2-3=(x-\sqrt{3})(x+\sqrt{3})$

so f(x)=0 for $x=\sqrt{3} \ or \ x = -\sqrt{3}$

so the correct answer is A)

hope this helps

3 0

3 years ago

Eduardo has a recipe that uses 2/3 cup of flour for each batch. If he makes 4 batches, how many cups of flour will he need? How

34kurt

Answer:

4 batches: $2\frac{2}{3}$ cups

7 batches: $4\frac{2}{3}$ cups

Step-by-step explanation:

If he uses 2/3 cup of flour for <u>each</u> batch, then that is 2/3 four times, or 2/3 · 4.

$\frac{2}{3}$ × $\frac{4}{1}$

= $\frac{8}{3}$ = $2\frac{2}{3}$

If he makes three more, than that will be 7 batches in total. We can multiply 2/3 by 3 to find out how much will be needed for those extra three, then add that product to $2\frac{2}{3}$ .

$\frac{2}{3}$ × $\frac{3}{1}$