Answer:
The coordinates of point t are (22,6)
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two point is equal to
![s=(\frac{x1+x2}{2},\frac{y1+y2}{2})](https://tex.z-dn.net/?f=s%3D%28%5Cfrac%7Bx1%2Bx2%7D%7B2%7D%2C%5Cfrac%7By1%2By2%7D%7B2%7D%29)
we have
s(6,4)
(x1,y1)=r(-10,2)
Let
t(x2,y2)
substitute the values
![(6,4)=(\frac{-10+x2}{2},\frac{2+y2}{2})](https://tex.z-dn.net/?f=%286%2C4%29%3D%28%5Cfrac%7B-10%2Bx2%7D%7B2%7D%2C%5Cfrac%7B2%2By2%7D%7B2%7D%29)
<em>Solve for x2</em>
![6=(-10+x2)/2\\12=-10+x2\\x2=12+10\\x2=22](https://tex.z-dn.net/?f=6%3D%28-10%2Bx2%29%2F2%5C%5C12%3D-10%2Bx2%5C%5Cx2%3D12%2B10%5C%5Cx2%3D22)
<em>Solve for y2</em>
![4=(2+y2)/2\\8=2+y2\\y2=8-2\\y2=6](https://tex.z-dn.net/?f=4%3D%282%2By2%29%2F2%5C%5C8%3D2%2By2%5C%5Cy2%3D8-2%5C%5Cy2%3D6)
therefore
The coordinates of point t are (22,6)
Answer:
2.
Step-by-step explanation:
The answer is the seocnd one.
Answer:
I am English read I know math not
Answer:
True.
If Δ ABC ≅ Δ DBC then BC bisects the angle ∠ ACD.
Step-by-step explanation:
Δ ABC ≅ Δ DBC
∠ ACB ≅ ∠ DCB {corresponding angles of congruent triangles}or(c.p.c.t)
i.e BC is the bisector of ∠ ACD
Hence, TRUE
Answer:
What numbers? Be specific.