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3 years ago

I need help to see if these are true or false.

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

7 0

Answer:

1. false

2. true

3. true

4. false

5. false

6. true

Step-by-step explanation:

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Zarrin [17]

Answer:

29500

Step-by-step explanation:

subtract the two numbers

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3 years ago

The skating rink rented 218 pairs of skates during the month of April and 3 times that many in May. How many pairs of skates did

Marrrta [24]

Answer: Total number of pairs =872

Step-by-step explanation:

Since we have given that

Number of pairs of skates during the month of April =218

Number of pairs of skates during the month of May =3 × 218=654

As we know that total means altogether in which we perform the additive operation.

Total pairs of skates the skating rent during April and May = 218+654=872

∴ Total number of pairs =872

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3 years ago

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What is the median for 6.0 6.0 7.0 7.0 8.0 9.0

Vladimir79 [104]

The word median means middle.

The median is 7.0 because it’s in the middle of the following numbers.

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2 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

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9 months ago