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SVEN [57.7K]
3 years ago
9

EASY MATH PLEASE HELP!!

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0
The answer is A.....
blsea [12.9K]3 years ago
3 0
The answer is A. If there are 3 thirds (1/3s) per yard and there are 6 yards, 3*6=18. Because the last cut will make two 1/3-yard segments, the answer is 17 cuts and not 18.
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What is an expression to represent the equation
Tatiana [17]

Answer:

8 + \frac{x}{4}

Step-by-step explanation:

I'm assuming you want an answer to the top section of the question.

We can start with 8.

    8

When a problem asks for the sum, it's looking for addition, so we use the + sign.

    8 +

The problem says "a number," so let's represent that with x. Basically, x just means a number we don't know.

    8 + x

The "number" is divided by 4, so we'll just put x/4 as our second term.

   8 + \frac{x}{4}

7 0
3 years ago
HELP A MEEEE whats 1Million x 1Million
seraphim [82]

Answer:

one trillion

Step-by-step explanation:

5 0
3 years ago
Daniel wants to do 312 practice problems to prepare for an exam. if he wants to do approximately the same number of problems eac
alexandr1967 [171]

Answer:

Step-by-step explanation:

6 0
3 years ago
The density of water is 1 gram per cubic centimeter. A more dense object will sink, and a less dense object will float. Will a m
Bogdan [553]
Ah clever. So you need two formulas.

1) Volume of the marble.

   4(pi)r^3/3
= 4(pi)(1.4)^3/3
<span>= 11.49 (approx)
</span>
2) Formula for density.
  
    D = M / V
        = 9 / 11.49
        = 0.78

0.78 < 1

Therefore the marble will float.

8 0
3 years ago
Read 2 more answers
The plans for a new ammusement park were laid out on the first quadrant of a coordinate plane. The entrance to the roller coaste
Solnce55 [7]

The first step is to determine the distance between the points, (1,1) and (7,9)

We would find this distance by applying the formula shown below

\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}

Distance = 10 units

If one unit is 70 meters, then the distance between both entrances is

70 * 10 = 700 meters

4 0
1 year ago
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