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Fynjy0 [20]
3 years ago
6

Give an example of a chance experiment with four possible outcomes. (Select all that apply.) A. rolling a standard die B. pickin

g one of four unique cards C. a random number generator is used to select a whole number between 1 and 4 inclusive D. flipping two coins E. drawing a card from a deck Need Help? Talk to a Tutor Save Proarese
Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Answer:

A. rolling a standard die B. picking one of four unique cards C. a random number generator is used to select a whole number between 1 and 4 inclusive D. flipping two coins E. drawing a card from a deck

All are examples of a chance experiment with four possible outcomes.

Step-by-step explanation:

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Danielle earns $36.80 for 4 hours of yardwork. MacKenzie earns $50.40 for 6 hours of yardwork.Who earns more money per hour? How
Fantom [35]

Answer:

Danielle earns $1.20 more than Mackenzie (per hour)

Step-by-step explanation:

To find out how much money per hour each person earns, you would divide the earinings by the number of hours;

Danielle: $36.80/4 = $9.20 per hour

MackKenzie: $50.40/6 = $8.40 per hour

To find out how much extra Danielle earns, you would subtract 8.40 from 9.20;

9.40 - 8.20 = $1.20

Thus, Danielle earns $1.20 more than Mackenzie per hour.

6 0
3 years ago
Find the measure of 0. (To the nearest tenth)<br> A) 28.8<br> B) 33.4<br> C) 61.2<br> D) 63.4
Wewaii [24]

Answer:

B

Step-by-step explanation:

Hope this helps

4 0
3 years ago
List multiples to find the lcm 10<br> , 15
morpeh [17]
10-- 10,20,30,40,50,60,70,80,90
15-- 15,30,45,60,75,90,105
here are a few. The LCM would be 30.
I hope this helps!!
6 0
4 years ago
Read 2 more answers
Write words to match the expression 36 ÷ 4
Alenkasestr [34]
Thirty six divided by four is equal to nine
6 0
3 years ago
Read 2 more answers
Plzz HELP FOR POINTS AND BRAINLIST ANSWER
storchak [24]

A)Plugging in our initial statement values of y = 16 when x = 10, we get:

16 = 10k

Divide each side by 10 to solve for k:

16/10=

 k = 1.6

Solve the second part of the variation equation:

Because we have found our relationship constant k = 1.6, we form our new variation equation:

y = 1.6x

Since we were given that x, we have

y = 1.6()

y = 0


B)Plugging in our initial statement values of y = 1 when x = 15, we get:

1 = 15k

Divide each side by 15 to solve for k:

1/15

=15k

k = 0.066666666666667

7 0
3 years ago
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