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zaharov [31]
3 years ago
12

Solve for the unknown values

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
All you should have to do is take 180-95 to get 85 for x & then take 85+45= 130 - 180 = 50.

x=85 & y=50
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How do I subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 ?
SVETLANKA909090 [29]
-2m^2+4mn-6n^2

1) Let's write out both expressions subtracting 4m²+2mn+8n² from 2m²+6mn+2n²

\begin{gathered} 2m^{2}+6mn+2n^{2}-(4m^{2}+2mn+8n^2)_{} \\ 2m^2+6mn+2n^2-4m^2-2mn-8n^2 \\ -2m^2+4mn-6n^2 \end{gathered}

2) Note that when we subtract 4m^2 + 2mn + 8n^2 from 2m^2 + 6mn + 2n^2 we need to swap the sign by placing -1 outside the parentheses and then combine like terms adding those terms algebraically.

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The rectangle below is enlarged using a scale factor of 1.5. What will be the new length and width of the rectangle?
Likurg_2 [28]

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It costs $20 per hour to bowl and $3 for the shoes rental. Write an algebraic expression to represent the cost for n hours. How
ValentinkaMS [17]
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Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Ksenya-84 [330]

<u>Part a)</u> Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours  

we know that

x+y \leq20 --------> inequality 1  

6x+10y \geq 75 --------> inequality 2

<u>Part b)</u> Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

x+y \leq20 --------> inequality 1

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 1

6x+10y \geq 75 --------> inequality 2  

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 2

<u>Part c)</u> Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

x+y \leq20 --------> inequality 1

6x+10y \geq 75 --------> inequality 2

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N  3

Let

A(10,10) ------> see the attached figure N  3

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

<u>Prove algebraically </u>

A(10,10)

substitute the value of x and y in the inequalities

<u>inequality 1</u>

10+10 \leq20

20 \leq20 ------> is ok

<u>inequality 2</u>

6*10+10*10 \geq 75

160 \geq 75 -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0
3 years ago
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