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3 years ago

Which of the relations had a domain of (-5,0,5)

Mathematics

1 answer:

tigry1 [53]3 years ago

7 0

Answer:

Relation B had a domain of -5,0,5

Hope that helped

*befri.stends

Step-by-step explanation:

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HELP ME WITH ALL OF THESE ASAP i will give BRAINEST

lana66690 [7]

Answer:

The first is true.

8 · 21 = 168

The second is false.

The third is false.

The fourth is true.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A playing field is rectangular with a length of 100 yards and a width of 53 yards, 1 foot. If a player runs diagonally across t

musickatia [10]

First convert yards to feet.

1 yard = 3 feet.

100 x 3 = 300 feet long.

53 x 3 = 159 + 1 = 160 feet wide.

Now use the Pythagorean theorem to find the diagonal.

x^2 = 300^3 + 160^2

x^2 = 90000 + 25600

x^2 = 115600

x = √115600

x = 340 feet

4 0

3 years ago

A square patio has a perimeter of (32x+8) feet. What is the length of the patio?

kotykmax [81]

<h3>Hello There!!</h3>

<u>Given</u>

Perimeter = (32x + 8)

<u>To </u><u>Find</u>

Length of the Patio

<u>We Know,</u>

$\text{Perimeter of Square = 4 × sides}$

$\text{ 32x + 8} = 4 \times \text{sides} \\ \\ \fbox{dividing each side with 4} \\ \\ \implies \text{( 32x} \div 4) + (8 \div 4) = \frac{4 \times \text{sides}} {4} \\ \\ \implies \text{8x + 2} = \frac{ \cancel4 \times \text{sides}} { \cancel4} \\ \\ \implies \text{sides} = \text{8x + 2}$

$\therefore \text{ Length of the Patio} = \text \red{ \underline{8x + 2 feet}}$

<h3>Hope this helps!!</h3>

6 0

2 years ago

Solve the equation (linear equation)<br><br> <img src="https://tex.z-dn.net/?f=8%5E%7B2x%2B7%7D%20%3D%20%28%5Cfrac%7B1%7D%7B32%7

Minchanka [31]

Answer: $x=-1$

Step-by-step explanation:

By the negative exponent rule, you have that:

$(\frac{1}{a})^n=a^{-n}$

By the exponents properties, you know that:

$(m^n)^l=m^{(nl)}$

Therefore, you can rewrite the left side of the equation has following:

$(\frac{1}{8})^{-(2x+7)}=(\frac{1}{32})^{3x}$

Descompose 32 and 8 into its prime factors:

$32=2*2*2*2*2=2^5\\8=2*2*2=2^3$

Rewrite:

$(\frac{1}{2^3})^{-(2x+7)}=(\frac{1}{2^5})^{3x}$

Then:

$(\frac{1}{2})^{-3(2x+7)}=(\frac{1}{2})^{5(3x)}$

As the base are equal, then:

$-3(2x+7)=5(3x)$

Solve for x:

$-6x-21=15x\\-21=15x+6x\\-21=21x\\x=-1$

8 0

3 years ago

Helppppp PLEASE please please

Westkost [7]

F(x) = 30.eˣ
We notice that the graph intercept y-axis at 30
in f(x) = 30.eˣ , for x=0, e⁰ =1 and f(x) = 30
In short it's the only function that has a y-intercept = 30 (answer B)

7 0

4 years ago