All categories

3 years ago

Write the equation of the line in slope intercept form that passes through the two points: (1,-6) and (-3,2)

Mathematics

1 answer:

tatiyna3 years ago

5 0

Answer:

y = -2x - 4

Step-by-step explanation:

Formula is y = mx + b where m is the slope and b is the y-intercept

(1, -6) (-3, 2)

$\frac{-6-2}{1-(-3)}=\frac{-8}{4} =-2$

The slope is -2

y = -2x + b

So let's find b, insert 2 for y and -3 for x to find b

2 = -2(-3) + b

2 = 6 + b

Subtract 6 from both sides to get b alone

-4 = b

We found what b equals (the y-intercept), which is -4

So, the equation is y = -2x - 4

Hope this helps and pls do mark me brainliest:)

You might be interested in

Water boils at different temperatures at different elevations. The boiling temperature of water is 212 degrees * F sea level (0

Nikolay [14]

Answer:

The elevation when the boiling point of water is $190$ ° $F$ is 12790.70 feet

Step-by-step explanation:

Let every 1,000 feet of elevation be $x$ . Hence, we can write

$T = 212$ $- 1.72x$

Where $T$ is the boiling temperature of water at different elevations

Now, to the determine the elevation when the boiling point of water is $190$ ° $F$ .

We will determine $x$ by putting $T = 190$ ° $F$ .

Hence,

$T = 212$ $- 1.72x$

$190$ $= 212$ $- 1.72x$

$190 - 212$ $= - 1.72x$

$- 22$ $= - 1.72x$

$22 = 1.72x\\x = \frac{22}{1.72} \\x = 12.79070$

Since $x$ represents every 1,000 feet of elevation, then the elevation when the boiling point of water is $190$ ° $F$

$12.79070$ × $1000\\$ $= 12790.70$ feet

Hence, the elevation when the boiling point of water is $190$ ° $F$ is 12790.70 feet

8 0

4 years ago

Describe some similarities and differences between a situation that involves calculating surface area and a situation that invol

ki77a [65]

Usually when you are required to find the volume it’s when working with 3d objects or liquids

4 0

3 years ago

Read 2 more answers

Please solve the proof

Alenkinab [10]

Answer:

$\pi \pi \neq x^{2}$

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$ $\lim_{n \to \infty} a_n$

7 0

4 years ago

HELLLLLPPPP ASAP!!!!

Maurinko [17]

Answer:

1) 63.9%

2) 82.4%

3) 71.8%

4) 50%

5) 97%

6) 60%

3 0

3 years ago

Read 2 more answers

Suppose a consumer product researcher wanted to find out whether a highlighter lasted longer than the manufacturer's claim that

rosijanka [135]

Answer:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

Step-by-step explanation:

Data given and notation

$\bar X=14.5$ represent the sample mean

$s=1.2$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =14$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 14, the system of hypothesis would be:

Null hypothesis: $\mu \leq 14$

Alternative hypothesis: $\mu > 14$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{14.5-14}{\frac{1.2}{\sqrt{40}}}=2.635$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.635)=0.006$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis

The best option would be:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

4 0

3 years ago