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3 years ago

I NEED THIS ANSWERED FAST WITH WORK PLEASE

Mathematics

1 answer:

Pavel [41]3 years ago

3 0

1 thousand a month would be my guess

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Pls help it’s solve the expression it’s in the attatchmenr

kondor19780726 [428]

Answer:

$-16+\sqrt{31}$

Step-by-step explanation:

3 0

2 years ago

The number 0.35 is one thousandth of what number?

Anni [7]

Answer:

0.35 is one thousandth of 350

Step-by-step explanation:

Let

x ----> the number

we know that

The number multiplied by one thousandth must be equal to 0.35

The linear equation that represent this situation is

$(\frac{1}{1,000})x=0.35$

solve for x

Multiply both sides by 1,000

$1,000(\frac{1}{1,000})x=1,000(0.35)\\\\x=350$

therefore

0.35 is one thousandth of 350

6 0

2 years ago

Paul and Tom both commute to work. Paul's commute on the train takes 15 minutes more than one third as many minutes as Tom's com

Ronch [10]

Answer:

45 = (one third)x + 15

Step-by-step explanation:

If x represents the number of minutes Tom commutes, then (1/3)x is "one-third as many minutes as Tom's commute." 15 minutes more than that is ...

(1/3)x + 15

We are told this is the length of Paul's commute, and that it is 45 minutes. So, the appropriate equation is ...

45 = (1/3)x +15

8 0

3 years ago

write the formula for absolute value function if its graph has the vertex at point (0,6) and passes through the point (-1,-2)

Readme [11.4K]

Answer:

First you need to find the slope of the line:

m=6-(-2) / (-1)-0 =-8

equation of line is:

y=mx+b

y=-8x+6

for absolute value function:

if x<0

y=-8x+6

if x>0

y=+8x-6

Step-by-step explanation:

8 0

1 year ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago