Answer:
Well none of the answers are correct as maximum height is found by doing -b/2a which gives the x coordinate of the vertex also known as the heighest or lowest point. But when plugged in it gives the lowest point assuming you made the mistake of making the 16 positive when its supposed to be negative you would plug it in and get 98 which isn't an answer choice assuming 34 is the ground when you subtract that you get 64 whch still isn't an answer choice check your numbers in the equation
If it’s in slope intercept I pretty sure the slope should be 5 because if y=mx+b and the m is slope then slope should be 5
Answer:
The correct answer is option D. Dilation by a scale factor of 2 followed by reflection about the x-axis
What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)
Three consecutive integers are . . . x, x+1, and x+2
The smallest two are . . . x and x+1
Their product is . . . . . x(x+1)
5 times the largest one is . . . 5(x+2)
5 less than that is . . . . . . 5(x+2)-5
Now, the conditions of the problem say that <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .
Eliminate parentheses: x² + x = 5x + 10 - 5
Combine like terms: x² + x = 5x + 5
Subtract 5x from each side: x² - 4x = 5
Subtract 5 from each side: <u>x² - 4x - 5 = 0</u>
You could solve that by factoring it, or use the quadratic equation.
Factored, it says that (x + 1) (x - 5) = 0
From which <em>x = -1</em>
and <em>x = +5</em>
We only want the positive results, so our three consecutive integers are
5, 6, and 7 .
To answer the question, the smallest one is <em><u>5 </u></em>.
<u>Check</u>:
5 x 6 ? = ? (7 x 5) - 5
30 ? = ? (35) - 5
30 = 30
yay !
Answer: 50%
Step-by-step explanation:
