The surface area of the right triangular prism is 270 sq ft
<h3>Total surface ara of the prism</h3>
The total surface area of the prism is the sum of all the area of its faces
For the two triangles
A = 2(0.5bh)
A = bh
A = 7 * 12 = 84 sq.ft
For the two rectangles
A = 2lw
A = 2(6*12)
A = 2 * 72 = 144 sq.ft
For the third triangle;
Area 6ft * 7ft
Area = 42 sq.feet
Taking the sum of the areas
TSA = 84 + 144 + 42
TSA = 270 sq ft
Hence the surface area of the right triangular prism is 270 sq ft
Learn more on surface area of prism here; brainly.com/question/1297098
Slope intercept form: y = mx + b
m = slope
b = y-intercept
The line passes through the y-axis at the point (0, -5). So, -5 is the y-intercept.
We can use the points (0, -5) and (5, 0) to solve.
Slope formula: y2-y2/x2-x1
0-(-5)/5-0)
5/5
1
The slope is 1.
Substitute these values into the equation.
y = 1x + (-5)
y = x - 5
Therefore, the answer is [ y = x - 5 ]
Best of Luck!
The first one is the second one. t(n)=20n+480
Question 4: is the first one t(n)=8n+15
Answer:
angle NMP = 63°
angle LMP = 74°
Step-by-step explanation:
Let angle NMP be x° . It's given that angle LMP is 11° more than angle NMP. So, angle LMP = x° + 11°
But angle NML = 137°.
So,
angle NMP + angle LMP = 137°
=> x° + x° + 11° = 137°
=> 2x° + 11° = 137°
=> 2x° = 137° - 11°
= 126°
=> x° = 126/2 = 63°
angle NMP = 63°
angle LMP = 63 + 11 = 74°
Answer:
2.64
Step-by-step explanation:
The sqhate root of 7 is 2.64575131106. Usually this would be 2.64 when rounded to nearest hundredth.
