2 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

denis-greek [22]2 years ago

7 0

I’m pretty sure the answer is c (not that sure tho)

vichka [17]2 years ago

3 0

i beleve its C the 3d one down from the top

You might be interested in

In triangle MPQ points N and R are located on sides MP and QP with NR drawn. which set of measurements below would justify that

NNADVOKAT [17]

The answer is number 1. Because 12/10 =20/18 is a true statement. None of the others are true

6 0

2 years ago

the function of y= x^2 - 4x + 8 approximates the height y, of a bird and its horizontal distance, x as it flies from one fence p

Vika [28.1K]

Rewrite the given equation as
$y=x^2-4x+8=x^2-4x+4+4=(x-2)^2+4$ .
Since $(x-2)^2\ge 0$ , you can conclude that the imimum value of y will be gained for the minimum value of $(x-2)^2$ . The minimum value of $(x-2)^2$ is 0 for x=2.
So, y(2)=0+4=4.
Answer: minimum value of y is 4, when x=2.

7 0

2 years ago

Read 2 more answers

Amina was asked to write the prime factorization of 525

ioda

Answer:

Prime factorization of 525 is 3×5×5×7

6 0

2 years ago

Read 2 more answers

Which equations are related equations to x + 5 = 34?

myrzilka [38]

Answer:

the answer is 5=34−x and x=34−5

Step-by-step explanation:

i just got finished taking the test in 7th grade k12

3 0

3 years ago

Niobium-91 has a half-life of 680 years. After 2,040 years, how much niobium-91 will remain from a 300. 0-g sample? 3 g 18. 75 g

alekssr [168]

Answer:

Amount of Niobium-91 initially

= 300/91 =3.2967mol

2040 years = 3 ×680 = 3 half-lives

therefore, amount left = 0.4121mol

mass of Niobium-91 remaining = 0.4121 ×91 =37.5g

Please give brainliest

8 0

2 years ago