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Pachacha [2.7K]
3 years ago
13

Fill in the missing terms for the geometric sequence

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Step-by-step explanation:

<em>1</em><em>1</em><em>/</em><em>2</em><em>,</em><em> </em>-11, 22, <em>-</em><em>4</em><em>4</em><em>,</em><em> </em>88, -176

common ratio : 22/(-11) = -2

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emmasim [6.3K]

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3 years ago
What is the surface area!!
Greeley [361]

Answer:

450

Step-by-step explanation:

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When 0 is substituted for x, in the equation what is y? <br><br><br> y=x^2-2x+2
Leto [7]

Answer:

2

Step-by-step explanation:

We have y=x²-2x+2

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Hope this helps

4 0
3 years ago
Read 2 more answers
If the basalt at the top of the ancient valley below Vulcan's Throne yields a radiometric date (K-Ar) of 15,000 years, and the l
zepelin [54]

Answer:

1.69\times 10^3feet/million year

Step-by-step explanation:

We are given that

Elevation of top of basalt in valley =4100 feet

Elevation of bottom of basalt in valley =2100 feet

Age of top of basalt in valley=15000 years

Age of bottom of basalt in valley=1.2 million years=1.2\times 10^6 years=1200000 years

We have to find the rate of basalt filling in the valley in feet per million yeas

Rate of basalt filling in the valley=\frac{Elevation\;of\;top\;of\;basalt\;in\;valley-elevation\;of\;bottom\;of\;basalt\;in\;valley}{age\;of\;bottom\;of\;basalt\;in\;valley-age\;of\;top\;of\;basalt\;in\;valley}

Rate of basalt filling in the valley=\frac{4100-2100}{1200000-15000}=\frac{2000}{1185000}=1.69\times 10^{-3} feet/year

Rate of basalt filling in the valley=1.69\times 10^{-3}\times 10^{6}=1.69\times 10^3feet/million year

6 0
4 years ago
sara spent $ 2.30 on sweets , $ 3.20 on a pencil and $ 9.15 on an excerise book . What steps would you use to find out much less
user100 [1]
2.30 plus 3.20 and 9.15 is 14.65 .
8 0
3 years ago
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