Answer:
w = 19
L = 6
Step-by-step explanation:
L = w - 13
a = lw
114 = w(w - 13)
114 = w² - 13w
w² - 13w - 114
(w - 9) (w + 6)
w ≠ -6 (a length cannot be negative)
w = 19
L = 19 - 13
L = 6
1 -4
2 -10
3 10
4 -21
and you will need to figure the rest out
Answer:
The region with the highest population density is Binky Lee
The region with the lowest population density is ChesLen
Step-by-step explanation:
The population density is the total number of people per unit of land area.
Population density = Total population / land area
Beer Creek = 12,624/3,412
= 3.6998827667057
Approximately, 3.7
Binky Lee = 462/112
= 4.125
Approximately, 4.1
ChesLen = 3,537/1,263
= 2.8004750593824
Approximately, 2.8
Crow's nest = 2,142/612
= 3.5
The region with the highest population density is Binky Lee
The region with the lowest population density is ChesLen
Answer:
Correct option:
(B) <em>H₀</em>: <em>μ</em> = 2.40 vs. <em>Hₐ</em>: <em>μ</em> ≠ 2.40.
Step-by-step explanation:
The registrar of particular university in 1975 plans to look at records of students graduating last year to see if the mean GPA has changed from 2.40.
The registrar can use a single mean test to determine whether the mean has changed or not.
The hypothesis can be described as:
<em>H₀</em>: The mean GPA is 2.40, i.e. <em>μ</em> = 2.40.
<em>Hₐ</em>: The mean GPA is different from 2.40, i.e. <em>μ</em> ≠ 2.40.
To perform the test the registrar can either use a <em>z</em>-distribution or a <em>t</em>-distribution.
If the data provided gives some insight about the population standard deviation and the sample selected is quite large then the <em>z</em>-distribution can be used.
Otherwise it is wiser to use a <em>t</em>-distribution.
The decision rule is:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Thus, the correct option is (B).