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vfiekz [6]
3 years ago
9

Parallelogram JKLM is shown on the coordinate plane below:

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0
The real answer is b
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Solve for h: a = 1/2bh<br><br> h = A over 2b<br> h = A/b (1 /2)<br> h = 2Ab<br> h = 2A/b
Alborosie
The answer is: A=(1/2)bh&#10;2A=2(1/2)bh&#10;&#10;2A=bh&#10;&#10;(2A)/b=(bh)/b&#10;&#10;h=2A/b&#10;
5 0
3 years ago
Solve.
ZanzabumX [31]

Answer:

ok the answer is C

Step-by-step explanation:

1.75*4=7

.75*2=1.5

7+1.5=8.50

8 0
3 years ago
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Which expression represent the approximate length of BC HEEEEELLLLPPP!!!
Bumek [7]

Answer:

A

Step-by-step explanation:

Using the Sine rule in Δ ABC

\frac{sinA}{BC} = \frac{sin38}{AB} , substitute values

\frac{sin66}{BC} = \frac{sin38}{3} ( cross- multiply )

BC sin38° = 3 sin66° ( divide both sides by sin38° )

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5 0
3 years ago
Please help look at the picture
k0ka [10]

Answer:

y = - 5x - 1

Step-by-step explanation:

The first thing to do (always) is pay attention to x =0. That at least gives you a partial answer. y = y' - 1. when you put 0 in for whatever y' is you get 0. What about the other numbers? How did they come about.

We have another clue. Whenever you put in a positive number for x, you get a negative answer for y. That's interesting. So y' has a minus sign associated with it.

y = -ax - 1    Make a>0 so there is only 1 minus sign. x cannot have an even power, because an even power would make everything positive except the -1.  

So we'll start with y= - ax - 1 We'll also make the assumption that a = 1

y = - x - 1 That won't work. a >1 otherwise x = 2 won't give - 11

y = -ax - 1

let x = 2

let y = - 11 Solve for a

y = - ax - 1

- 11 = -a*-2 - 1       add   1  to both sides

-11 + 1 = - a(-2) - 1 + 1

- 10 = -2a             Divide by - 2

- 10/-2 = -2a/-2

a = 5

Answer: y = - 5x - 1

8 0
3 years ago
Shaded area=40<br> Find x <br> Width=3x<br> Length=4x<br> Not shaded area=2x
Mashutka [201]
In the process of laying out the question, you have given us important facts about the shaded area and the unshaded area. Now step back for just a second. If they're that deeply involved in the question, do you honestly expect that anybody can answer the question without seeing the picture of them ? ! ?
6 0
3 years ago
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