Based on the information given, the value of the area of the irregular figure will be 13.7 ft².
<h3>How to calculate the area.</h3>
From the complete question, the area of a triangle will be:
= 0.5 x base x height
= 0.5 x 3.6 x 4.8
= 8.64 ft²
Area of the semicircle = 0.5πr²
Area of the semicircle = 0.5 x 3.14 x 1.8²
Area of the semicircle = 5.09 ft²
Area of the irregular figure = Area of the semicircle + Area of the triangle
= 5.09 ft² + 8.64 ft²
= 13.73ft² = 13.7 ft²
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For this we will use kinematic equations.
We need the time of flight to compute the range.
With the given information, the most useful formula is:
Δy=v0yt−g2t2
Because our equation is taking only vertical motion into account,
v0y=30sin(45)
Because we are looking for the range of the object,
Δy=0
This leaves us with only one unknown: t
0=30sin(45)t−g2t2
g2t2=30sin(45)t
g2t=30sin(45)
t=60gsin(45)
For horizontal distance, the formula we need is:
Δx=v0xt
Because we are taking into account the horizontal range,
v0x=30cos(45)
In substituting our derived values into the equation we can see that:
Δx=30cos(45)∗60gsin(45)
Range=30cos(45)∗60gsin(45)
The angle formed between the line of pull of a muscle and the longitudinal axis of the bone in which the muscle is acting. The line of pull is usually indicated by the joint angle. It affects the strength of muscle action; at only certain angles of pull can a muscle exert maximal tension.
