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Sloan [31]
3 years ago
15

If angle A = 34°, angle B = (x-5)°, angle C = 4y °, what is the value of y?

Mathematics
2 answers:
nevsk [136]3 years ago
4 0
180-34=146
146-5=141
ratio=1:4
1+4=5
141÷5=28.2
x=28.2
y=112.8

I may be wrong, ask for more opinions
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BabaBlast [244]3 years ago
3 0

The answer to your question 28

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Write 5 Expressions that are equivalent to 20x + 100
lutik1710 [3]
40X+200

60X+300

80X+400

7 0
4 years ago
FREE BRAINLIEST!! ill also answer questions that you have posted if you answer correctly!!!! (32pts)
OlgaM077 [116]

Answer:

there is enough info to determine the figure... also the answer is D Hope this helps

Step-by-step explanation:

4 0
3 years ago
Which ones are rational
Alenkasestr [34]
A rational number is a number that can be made by dividing two integers. An integer is a number that doesn't have a fraction part.

1. 2.4 - rational
2. 74 - rational
3. 17.3333333… - rational
4. π -irrational
5. there is no number
6. –18 - rational
7. there is no number
8. 87.125 - rational
9. –30 - rational
10. –8.3 -rational
11. 58.25 -rational
12. 121 -rational
13. 4.5 -rational
14. 3 7/10 -rational

As you can see, most numbers are rational. But, when you come across pi or when you have a decimal that goes on forever without repeating (like some square roots), it tends to be irrational.
3 0
3 years ago
Can u help me pls they are exponents with multiplication and division
Ronch [10]
When there is a multiplication involving exponents, we need to evaluate the numbers and each variables separately. In this case, we have 5 and 4 as the numbers, and w and h for the variables.

When we multiply 5 and 4 we get:
5 \times 4 = 20

For w, we have {w}^{6}, {w}^{4}, w. While we are multiplying the w's, we need to add the exponents together to get the final answer: {w}^{6} \times {w}^{4} \times w = {w}^{11}

For h's, there are {h}^{2}, {h}^{5}, {h}^{4}. When we apply the same thing to h's, we get {h}^{2} \times {h}^{5} \times {h}^{4} = {h}^{11}

For the final step, we need to write all of these together: 20 \times {w}^{11} \times {h}^{11} \: \: or \: \: 20 {w}^{11} {h}^{11} \: \: or \: \: 20 {(wh)}^{11}
3 0
4 years ago
How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
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