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2 answers:
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Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is
So, area of square base is 100 sq. in.
Area of a triangle is
So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.
Therefore, the area of the pyramid is 180 sq. in.
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A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
- Find the Area of the Space.
"If the 2 is quantity use multiply it again"
<h3>••••••••••••••••••••••••••••••••••••••••••••••••</h3><em>NOTE:</em>The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).
"Problem has been solve"
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