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uranmaximum [27]
3 years ago
9

It costs $12 to attend a golf clinic with a local pro. Buckets of balls for practice during the clinic cost $3 each. How many bu

ckets can you buy at the clinic if you have $30 to spend?
plz i beg
Mathematics
2 answers:
iVinArrow [24]3 years ago
5 0
You can buy 6 buckets
Free_Kalibri [48]3 years ago
4 0
6 buckets ....................
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What is the sum of two numbers a and b decreased by their product?
natka813 [3]

Answer:

(a+b) - (ab)

Step-by-step explanation:

sum of two numbers a and b decreased by their product

(a+b) - (ab)

8 0
3 years ago
Read 2 more answers
Find the mean, median, mode, range, and standard deviation of the data set obtained after multiplying each value by 2. Round to
Elena L [17]

Answer:

mean: 8.9, median: 9, mode: 3, range: 14, standard deviation: 5.1

Step-by-step explanation:

The mean is all the numbers added up, divided by how many numbers there are. To get the median you arrange the numbers biggest to smallest and find the middle number.

7 0
3 years ago
Read 2 more answers
Use the elimination method to solve the system of equations.Choose the correct ordered pair. -x + y -2 , 2x -3y = 4​
AnnZ [28]

Answer:

To use the elimination method one coefficient of either x or y must be the same number with opposite signs, so the ordered pair is (-10, -8)

Step-by-step explanation:

2(-x+y=2) Make one of the coefficients equal, with opposite signs.

2x-3y=4  Combine equations.

-y=8 Solve, y=-8

Then find x, -x-8=2

-x=10, so x= -10

(-10, -8) is your answer.

6 0
2 years ago
What is the square root of -2i?
Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of z=0-2i. First, convert from Cartesian to polar form:

r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2

\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}

z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})

Next, use the formula \displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr] where \displaystyle k=0,1,2,...\:,n-1 to find the square roots:

<u>When k=1</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]

\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)

\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i

<u>When k=0</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)

\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i

Thus, the square roots of -2i are 1-i and -1+i

4 0
2 years ago
What is the length of bc?
zhuklara [117]

Answer:

15 units

Step-by-step explanation:

ΔABC is right with ∠C = 90° and AB the hypotenuse

using Pythagoras' identity on the triangle

AB² = AC² + BC² , hence

BC² = AB² - AC² = 17² - 8² = 289 - 64 = 225

⇒BC = \sqrt{225} = 15 units


8 0
3 years ago
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