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3 years ago

Please answer fast!

Mathematics

1 answer:

pentagon [3]3 years ago

5 0

Answer:

4 and 2

Step-by-step explanation:

a positive times a negative makes a negative

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What are the solutions of the following equation?<br>4|x - 9| + 9 = -3|x - 9| + 9

Stells [14]

Answer:

X=9

Step-by-step explanation:

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3 years ago

Below is a series of steps Mel took to solve an equation. She got the wrong answer. Find Mel's mistake. Then, use order of opera

Inessa [10]

Answer: x = 9

Mel's mistake was in the last step, she multiplied by 2 instead of dividing by 2

Step-by-step explanation:

2x + 1 = 19

Subtract 1 from each side

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3 years ago

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Given h of x equals negative 2 times the square root of x minus 3 end root, which of the following statements describes h(x)?

Yuliya22 [10]

Using translation concepts, it is found that the correct option regarding the function is:

The function h(x) is decreasing on the interval (3, ∞).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is given by:

$f(x) = \sqrt{x}$

Which increases on (0, ∞).

The translated function is given by:

$g(x) = -2\sqrt{x - 3}$

With the translation, the domain is now (-3, ∞), and the function is decreasing, hence the correct option is given by:

The function h(x) is decreasing on the interval (3, ∞).

More can be learned about translation concepts at brainly.com/question/4521517

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2 years ago

Out of his monthly salary, Josh spends 37.5% on his bills, on groceries, and on transportation. If he decides to save of the rem

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3 years ago

Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

<u>Given quadratic equation</u>:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

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1 year ago

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