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3 years ago

How to solve this equation 2+6x=1-x

Mathematics

2 answers:

aleksley [76]3 years ago

8 0

+x on each side. Then -2 on each side. Then divide both sides by 6 and you have your answer

loris [4]3 years ago

8 0

×=-1/7 is the answer for that equation

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5x(x+6)=−50 i need to find the xs by completing the square

FrozenT [24]

5x(x+6)=-50 X(x+6)=-10 X square +6x=-10 (X+3) square=-10-9 (X+3) square=-19 So this equation has no solution

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3 years ago

12 male birds for every 9 female birds ratio

Alja [10]

Answer:

4:3

Step-by-step explanation:

You divide both of them by 3

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3 years ago

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The doctor has told Cal O'Ree that during his ten weeks of working out at the gym, he can expect each week's weight loss to be $

Sergio [31]

Answer:

220.67 pounds

Step-by-step explanation:

This problem can be treated as a compounded interest with a weekly rate of -1%. Cal's weight after 'n' weeks at a 1% loss rate per week is described by the following expression:

$W = 244*(1-0.01)^n$

For n = 10 weeks, Cal's weight is:

$W = 244*(1-0.01)^{10}\\W=220.67\ pounds$

He expects to weigh 220.67 pounds at the end of the ten weeks.

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3 years ago

Find the complex fourth roots of 81(cos(3π/8)+isin(3π/8)). a) Find the fourth root of 81. b) Divide the angle in the problem by

WARRIOR [948]

Answer:

The answer is below

Step-by-step explanation:

Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:

$z_1=r^{\frac{1}{n} }(cos(\frac{\theta +2k\pi}{n} )+isin(\frac{\theta +2k\pi}{n} )),\\k=0,1,2,.\ .\ .,n-1$

Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:

$z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\$

$z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]$

3 0

3 years ago

Can someone pls help me

Sophie [7]

Answer:

Step-by-step explanation:

If you divide 36 by 12, you get 3.

For this to work, whatever the white wax is, it needs to be 3 times as more as 5.

5x3=15

5 0

3 years ago

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